What are the solutions to the equation -4x^2-1=0 ?

The solutions to the equation -4x^2-1=0 are x= 1/2 i,x=-1/2 i

Find the zeros of -4x^2-1=0

The zeros of -4x^2-1=0 are x= 1/2 i,x=-1/2 i

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- 4 x^{2} - 1 = 0

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

- 4 x^{2} - 1 = 0

Move

1

to the right side

- 4 x^{2} = 1

Divide both sides by

- 4

x^{2} = - \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{4}, x = - - \frac{1}{4}

- \frac{1}{4} = \frac{1}{2} i

- - \frac{1}{4} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

2 x^{2} + 3 x - 6 = 0

\frac{7 - i}{- 1 + 3 i}

8 1^{- \frac{5}{4}}

∣ x ∣ < 9

2 v + 9 = 8 v + 21

What are the solutions to the equation -4x^2-1=0 ?
The solutions to the equation -4x^2-1=0 are x= 1/2 i,x=-1/2 i
Find the zeros of -4x^2-1=0
The zeros of -4x^2-1=0 are x= 1/2 i,x=-1/2 i