What is ((2x^{-3})/(xy^2))^{-2} ?

The solution to ((2x^{-3})/(xy^2))^{-2} is (x^8y^4)/4

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simplify ((2x^{-3})/(xy^2))^{-2}

simplify

(\frac{2 x ^{- 3}}{x y ^{2}})^{- 2}

\frac{x ^{8} y ^{4}}{4}

Solution steps

(\frac{2 x ^{- 3}}{x y ^{2}})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{2 x ^{- 3}}{x y ^{2}})^{- 2} = \frac{1}{( \frac{2 x ^{- 3}}{x y ^{2}} ) ^{2}}

= \frac{1}{( \frac{2 x ^{- 3}}{x y ^{2}} ) ^{2}}

Simplify

(\frac{2 x ^{- 3}}{x y ^{2}})^{2} : \frac{4}{x ^{8} y ^{4}}

= \frac{1}{\frac{4}{x ^{8} y ^{4}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{8} y ^{4}}{4}

\frac{- 28}{- 4}

(6 - x) (2 + x)

\frac{\frac{1}{x + 1} - 1}{x}

i^{- 35}

(- 3 - 2 i) - (11 + 10 i)

What is ((2x^{-3})/(xy^2))^{-2} ?
The solution to ((2x^{-3})/(xy^2))^{-2} is (x^8y^4)/4