What are the solutions to the equation x^2+14x+32=-8 ?

The solutions to the equation x^2+14x+32=-8 are x=-4,x=-10

Find the zeros of x^2+14x+32=-8

The zeros of x^2+14x+32=-8 are x=-4,x=-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 14 x + 32 = - 8

x = - 4, x = - 10

Solution steps

x^{2} + 14 x + 32 = - 8

Move

8

to the left side

x^{2} + 14 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 40 = 6

x_{1, 2} = \frac{- 14 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 6}{2 \cdot 1}, x_{2} = \frac{- 14 - 6}{2 \cdot 1}

x = \frac{- 14 + 6}{2 \cdot 1} : - 4

x = \frac{- 14 - 6}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 4, x = - 10

\frac{5}{9} - \frac{1}{3}

(x - 2) (x + 2) = 3 x

\frac{x ^{2} - 6 x + 8}{x ^{2} + 14 x + 49} \geq 0

- x^{2} + 10 x - 21 - (3 x - 15) \leq 0

ln ∣ 2 ∣

What are the solutions to the equation x^2+14x+32=-8 ?
The solutions to the equation x^2+14x+32=-8 are x=-4,x=-10
Find the zeros of x^2+14x+32=-8
The zeros of x^2+14x+32=-8 are x=-4,x=-10