What are the solutions to the equation -x^2-111x-28=0 ?

The solutions to the equation -x^2-111x-28=0 are x=-(111+sqrt(12209))/2 ,x=-(111-sqrt(12209))/2

Find the zeros of -x^2-111x-28=0

The zeros of -x^2-111x-28=0 are x=-(111+sqrt(12209))/2 ,x=-(111-sqrt(12209))/2

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- x^{2} - 111 x - 28 = 0

x = - \frac{111 + 12209}{2}, x = - \frac{111 - 12209}{2}

Decimal Notation

x = - 110.74717 \dots, x = - 0.25282 \dots

Solution steps

- x^{2} - 111 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 111 ) \pm ( - 111 ) ^{2} - 4 ( - 1 ) ( - 28 )}{2 ( - 1 )}

(- 111)^{2} - 4 (- 1) (- 28) = 12209

x_{1, 2} = \frac{- ( - 111 ) \pm 12209}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 111 ) + 12209}{2 ( - 1 )}, x_{2} = \frac{- ( - 111 ) - 12209}{2 ( - 1 )}

x = \frac{- ( - 111 ) + 12209}{2 ( - 1 )} : - \frac{111 + 12209}{2}

x = \frac{- ( - 111 ) - 12209}{2 ( - 1 )} : - \frac{111 - 12209}{2}

The solutions to the quadratic equation are:

x = - \frac{111 + 12209}{2}, x = - \frac{111 - 12209}{2}

2 x^{2} + 9 x + 7 = 0

x + 5 \leq 13

4 (2 + a) = 24

4 x^{2} + 5 x - 3 = 0

x^{3} - 6 x^{2} - 9 x + 54

What are the solutions to the equation -x^2-111x-28=0 ?
The solutions to the equation -x^2-111x-28=0 are x=-(111+sqrt(12209))/2 ,x=-(111-sqrt(12209))/2
Find the zeros of -x^2-111x-28=0
The zeros of -x^2-111x-28=0 are x=-(111+sqrt(12209))/2 ,x=-(111-sqrt(12209))/2