What are the solutions to the equation z^2+5z-14=0 ?

The solutions to the equation z^2+5z-14=0 are z=2,z=-7

Find the zeros of z^2+5z-14=0

The zeros of z^2+5z-14=0 are z=2,z=-7

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z^{2} + 5 z - 14 = 0

z = 2, z = - 7

Solution steps

z^{2} + 5 z - 14 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

z_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 5 + 9}{2 \cdot 1}, z_{2} = \frac{- 5 - 9}{2 \cdot 1}

z = \frac{- 5 + 9}{2 \cdot 1} : 2

z = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

z = 2, z = - 7

7 b - 52 = 6 b - 57

x^{2} + 10 x + 12 = 2 x + 5

- 3 \cdot - 15

9 w - 4 \geq 7 + 11 w

- x^{3} + 7 x^{2} - 14 x + 8

What are the solutions to the equation z^2+5z-14=0 ?
The solutions to the equation z^2+5z-14=0 are z=2,z=-7
Find the zeros of z^2+5z-14=0
The zeros of z^2+5z-14=0 are z=2,z=-7