What is factor 1-16ax^2+64a^2x^4 ?

The solution to factor 1-16ax^2+64a^2x^4 is (8x^2a-1)^2

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factor 1-16ax^2+64a^2x^4

factor

1 - 16 a x^{2} + 64 a^{2} x^{4}

(8 x^{2} a - 1)^{2}

Solution steps

1 - 16 a x^{2} + 64 a^{2} x^{4}

Factor

1 - 16 x^{2} a + 64 x^{4} a^{2} : (8 x^{2} a - 1) (8 x^{2} a - 1)

= (8 x^{2} a - 1) (8 x^{2} a - 1)

Apply exponent rule:

aa = a^{2}

(8 x^{2} a - 1) (8 x^{2} a - 1) = (8 x^{2} a - 1)^{2}

= (8 x^{2} a - 1)^{2}

\frac{3}{4 - 5}

\frac{2}{7} \div \frac{1}{8}

- \frac{3}{8} + (- \frac{9}{10})

\frac{( - 3 i ) ^{2} ( 1 - 2 i )}{2 + 2 i}

10 (m + 4 n)

What is factor 1-16ax^2+64a^2x^4 ?
The solution to factor 1-16ax^2+64a^2x^4 is (8x^2a-1)^2