What is the answer to (3-x)*10+x*20=0 ?

The answer to (3-x)*10+x*20=0 is x=-3

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(3-x)10+x20=0

(3 - x) \cdot 10 + x \cdot 20 = 0

x = - 3

Solution steps

(3 - x) \cdot 10 + x \cdot 20 = 0

Expand

(3 - x) \cdot 10 + x \cdot 20 : 30 + 10 x

30 + 10 x = 0

Move

30

to the right side

10 x = - 30

Divide both sides by

10

x = - 3

x^{2} + 2 x - 23 = 0

∣ x + 7 ∣ + 5 \leq 7

- 3 - 8 \leq - 23

4 - a^{2} - 2 ab - b^{2}

(9^{\frac{3}{8}})^{4}