What is (2x+1)*(2x-1)-(x+4)^2 ?

The solution to (2x+1)*(2x-1)-(x+4)^2 is 3x^2-8x-17

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simplify (2x+1)*(2x-1)-(x+4)^2

simplify

(2 x + 1) \cdot (2 x - 1) - (x + 4)^{2}

3 x^{2} - 8 x - 17

Solution steps

(2 x + 1) (2 x - 1) - (x + 4)^{2}

Expand

(2 x + 1) (2 x - 1) : 4 x^{2} - 1

= 4 x^{2} - 1 - (x + 4)^{2}

Expand

- (x + 4)^{2} : - x^{2} - 8 x - 16

= 4 x^{2} - 1 - x^{2} - 8 x - 16

Group like terms

= 4 x^{2} - x^{2} - 8 x - 1 - 16

Add similar elements:

4 x^{2} - x^{2} = 3 x^{2}

= 3 x^{2} - 8 x - 1 - 16

Subtract the numbers:

- 1 - 16 = - 17

= 3 x^{2} - 8 x - 17

- 45 \div 5

143 + 305 \cdot 701

(3 m^{2} n)^{4}

- 3 w + 9 q - 5 w

(4 - 2 i) + i (- 3 + 5 i)

What is (2x+1)*(2x-1)-(x+4)^2 ?
The solution to (2x+1)*(2x-1)-(x+4)^2 is 3x^2-8x-17