What is (2w^4v^{-5})^{-2} ?

The solution to (2w^4v^{-5})^{-2} is (v^{10})/(4w^8)

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simplify (2w^4v^{-5})^{-2}

simplify

(2 w^{4} v^{- 5})^{- 2}

\frac{v ^{10}}{4 w ^{8}}

Solution steps

(2 w^{4} v^{- 5})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(2 w^{4} v^{- 5})^{- 2} = \frac{1}{( 2 w ^{4} v ^{- 5} ) ^{2}}

= \frac{1}{( 2 w ^{4} v ^{- 5} ) ^{2}}

Simplify

(2 w^{4} v^{- 5})^{2} : \frac{4 w ^{8}}{v ^{10}}

= \frac{1}{\frac{4 w ^{8}}{v ^{10}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{v ^{10}}{4 w ^{8}}

2^{2} + 4^{2} + 6^{2}

(2 x + y^{2})^{2}

(6 x + 7) + (8 x^{2} + 5 x - 1)

- 27 \div 3

7 h - 5 - 4 h - 7

What is (2w^4v^{-5})^{-2} ?
The solution to (2w^4v^{-5})^{-2} is (v^{10})/(4w^8)