What is (x-1)/(x+3)>= 5 ?

The solution to (x-1)/(x+3)>= 5 is -4<= x<-3

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(x-1)/(x+3)>= 5

\frac{x - 1}{x + 3} \geq 5

- 4 \leq x < - 3

Solution steps

\frac{x - 1}{x + 3} \geq 5

Rewrite in standard form

\frac{- 4 x - 16}{x + 3} \geq 0

Factor

\frac{- 4 x - 16}{x + 3} : \frac{- 4 ( x + 4 )}{x + 3}

\frac{- 4 ( x + 4 )}{x + 3} \geq 0

Multiply both sides by

- 1

(reverse the inequality)

\frac{( - 4 ( x + 4 ) ) ( - 1 )}{x + 3} \leq 0 \cdot (- 1)

Simplify

\frac{4 ( x + 4 )}{x + 3} \leq 0

Divide both sides by

4

\frac{\frac{4 ( x + 4 )}{x + 3}}{4} \leq \frac{0}{4}

Simplify

\frac{x + 4}{x + 3} \leq 0

Identify the intervals

- 4 \leq x < - 3

(- 33 - 2 i) - (50 + 9 i)

\frac{x + 5}{4} = - 4

\frac{1}{4} + \frac{1}{4}

∣ - 15 ∣

5 (y - 4)^{2} = 80