What is (x^2+x+1)-(2x^2-3x-5) ?

The solution to (x^2+x+1)-(2x^2-3x-5) is -x^2+4x+6

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simplify (x^2+x+1)-(2x^2-3x-5)

simplify

(x^{2} + x + 1) - (2 x^{2} - 3 x - 5)

- x^{2} + 4 x + 6

Solution steps

(x^{2} + x + 1) - (2 x^{2} - 3 x - 5)

Apply rule:

(a) = a

(x^{2} + x + 1) = x^{2} + x + 1

= x^{2} + x + 1 - (2 x^{2} - 3 x - 5)

Apply the distributive law:

- (a - b) = - a + b

- (2 x^{2} - 3 x - 5) = - 2 x^{2} + 3 x + 5

= x^{2} + x + 1 - 2 x^{2} + 3 x + 5

Group like terms

= x^{2} - 2 x^{2} + x + 3 x + 1 + 5

Add similar elements:

x^{2} - 2 x^{2} = - x^{2}

= - x^{2} + x + 3 x + 1 + 5

Add similar elements:

x + 3 x = 4 x

= - x^{2} + 4 x + 1 + 5

Add the numbers:

1 + 5 = 6

= - x^{2} + 4 x + 6

12 - - 225 ab

(2 - 2 i)^{- 1}

\frac{x ^{2} + 5 x + 4}{x ^{2} + 3 x - 4}

10 x + 3 y + z - (5 x - 8 y + 3 z + 5 x - 2 y - 5 z)

(- 3) (4)

What is (x^2+x+1)-(2x^2-3x-5) ?
The solution to (x^2+x+1)-(2x^2-3x-5) is -x^2+4x+6