What is the answer to 4(7-3n)-4n=7(n+4) ?

The answer to 4(7-3n)-4n=7(n+4) is n=0

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4(7-3n)-4n=7(n+4)

4 (7 - 3 n) - 4 n = 7 (n + 4)

n = 0

Solution steps

4 (7 - 3 n) - 4 n = 7 (n + 4)

Expand

4 (7 - 3 n) : 28 - 12 n

28 - 12 n - 4 n = 7 (n + 4)

Add similar elements:

- 12 n - 4 n = - 16 n

28 - 16 n = 7 (n + 4)

Expand

7 (n + 4) : 7 n + 28

28 - 16 n = 7 n + 28

Move

28

to the right side

- 16 n = 7 n

Move

7 n

to the left side

- 23 n = 0

Divide both sides by

- 23

n = 0

49 x^{2} + 56 x + 16 = 0

\frac{1}{6} + \frac{1}{8}

100 = \frac{- 32 x ^{2}}{( 55 ) ^{2}} + x + 210

13 = t + 7

2 a a b^{2} - 3 a + 3 b a^{3}

What is the answer to 4(7-3n)-4n=7(n+4) ?
The answer to 4(7-3n)-4n=7(n+4) is n=0
Solve for n: 4(7-3n)-4n=7(n+4)
The solution is n=0