What is (x^2-4x)/(x^2-3x-4) ?

The solution to (x^2-4x)/(x^2-3x-4) is x/(x+1)

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simplify (x^2-4x)/(x^2-3x-4)

simplify

\frac{x ^{2} - 4 x}{x ^{2} - 3 x - 4}

\frac{x}{x + 1}

Solution steps

\frac{x ^{2} - 4 x}{x ^{2} - 3 x - 4}

Factor

x^{2} - 4 x : x (x - 4)

= \frac{x ( x - 4 )}{x ^{2} - 3 x - 4}

Factor

x^{2} - 3 x - 4 : (x + 1) (x - 4)

= \frac{x ( x - 4 )}{( x + 1 ) ( x - 4 )}

Cancel the common factor:

x - 4

= \frac{x}{x + 1}

(\frac{y}{3 z ^{3}})^{- 2}

\frac{1 0 ^{6}}{( 1 0 ^{10} ) ^{- 2}}

(2 a + 6 b) (2 a - 6 b)

(1 - cos^{2} (x)) sec^{2} (x)

(3 x - 3)^{2} - 7 (3 x - 3) + 15