What are the solutions to the equation (x^2)/(12)-x/4 = 1/3 ?

The solutions to the equation (x^2)/(12)-x/4 = 1/3 are x=4,x=-1

Find the zeros of (x^2)/(12)-x/4 = 1/3

The zeros of (x^2)/(12)-x/4 = 1/3 are x=4,x=-1

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\frac{x ^{2}}{12} - \frac{x}{4} = \frac{1}{3}

x = 4, x = - 1

Solution steps

\frac{x ^{2}}{12} - \frac{x}{4} = \frac{1}{3}

Find Least Common Multiplier of

12, 4, 3 : 12

Multiply by LCM=

12

\frac{x ^{2}}{12} \cdot 12 - \frac{x}{4} \cdot 12 = \frac{1}{3} \cdot 12

Simplify

x^{2} - 3 x = 4

Move

4

to the left side

x^{2} - 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 4) = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 1}

x = \frac{- ( - 3 ) + 5}{2 \cdot 1} : 4

x = \frac{- ( - 3 ) - 5}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

50 = - 5 x^{2} + 200

(\frac{2 a ^{2}}{8 a ^{- 2}})^{- \frac{1}{2}}

q^{3} + a^{3}

- 3 x^{2} > 2 x - 1

\frac{a ^{4}}{a ^{2}}

What are the solutions to the equation (x^2)/(12)-x/4 = 1/3 ?
The solutions to the equation (x^2)/(12)-x/4 = 1/3 are x=4,x=-1
Find the zeros of (x^2)/(12)-x/4 = 1/3
The zeros of (x^2)/(12)-x/4 = 1/3 are x=4,x=-1