What is expand (x^2+1)(x+1)(x-1) ?

The solution to expand (x^2+1)(x+1)(x-1) is x^4-1

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expand (x^2+1)(x+1)(x-1)

expand

(x^{2} + 1) (x + 1) (x - 1)

x^{4} - 1

Solution steps

(x^{2} + 1) (x + 1) (x - 1)

Expand

(x^{2} + 1) (x + 1) (x - 1) : (x^{2} + 1) (x^{2} - 1)

= (x^{2} + 1) (x^{2} - 1)

Apply Difference of Two Squares

(x^{2} + 1) (x^{2} - 1) : x^{4} - 1

= x^{4} - 1

\frac{5}{6} - \frac{8}{15}

\frac{1}{a ^{- 1} + b ^{- 1}}

4 x (x)

\frac{37}{9}

What is expand (x^2+1)(x+1)(x-1) ?
The solution to expand (x^2+1)(x+1)(x-1) is x^4-1