What is (x^2-2x-8)/(x^2-4) ?

The solution to (x^2-2x-8)/(x^2-4) is (x-4)/(x-2)

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simplify (x^2-2x-8)/(x^2-4)

simplify

\frac{x ^{2} - 2 x - 8}{x ^{2} - 4}

\frac{x - 4}{x - 2}

Solution steps

\frac{x ^{2} - 2 x - 8}{x ^{2} - 4}

Factor

x^{2} - 2 x - 8 : (x + 2) (x - 4)

= \frac{( x + 2 ) ( x - 4 )}{x ^{2} - 4}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{( x + 2 ) ( x - 4 )}{( x + 2 ) ( x - 2 )}

Cancel the common factor:

x + 2

= \frac{x - 4}{x - 2}

\frac{t ^{2} - 9}{2 t ^{2} + 7 t + 3}

2 (3 + 8)

0 (- x)

\frac{2 - ( 18 - 3 x )}{( 18 - 3 x ) + 1}

\frac{3 + ( - 1 )}{2}