What are the solutions to the equation 4.9x^2-12x-70=0 ?

The solutions to the equation 4.9x^2-12x-70=0 are x=(10(6+sqrt(379)))/(49),x=(10(6-sqrt(379)))/(49)

Find the zeros of 4.9x^2-12x-70=0

The zeros of 4.9x^2-12x-70=0 are x=(10(6+sqrt(379)))/(49),x=(10(6-sqrt(379)))/(49)

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4.9 x^{2} - 12 x - 70 = 0

x = \frac{10 ( 6 + 379 )}{49}, x = \frac{10 ( 6 - 379 )}{49}

Decimal Notation

x = 5.19753 \dots, x = - 2.74855 \dots

Solution steps

4.9 x^{2} - 12 x - 70 = 0

Multiply both sides by

10

49 x^{2} - 120 x - 700 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 120 ) \pm ( - 120 ) ^{2} - 4 \cdot 49 ( - 700 )}{2 \cdot 49}

(- 120)^{2} - 4 \cdot 49 (- 700) = 20379

x_{1, 2} = \frac{- ( - 120 ) \pm 20 379}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- ( - 120 ) + 20 379}{2 \cdot 49}, x_{2} = \frac{- ( - 120 ) - 20 379}{2 \cdot 49}

x = \frac{- ( - 120 ) + 20 379}{2 \cdot 49} : \frac{10 ( 6 + 379 )}{49}

x = \frac{- ( - 120 ) - 20 379}{2 \cdot 49} : \frac{10 ( 6 - 379 )}{49}

The solutions to the quadratic equation are:

x = \frac{10 ( 6 + 379 )}{49}, x = \frac{10 ( 6 - 379 )}{49}

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What are the solutions to the equation 4.9x^2-12x-70=0 ?
The solutions to the equation 4.9x^2-12x-70=0 are x=(10(6+sqrt(379)))/(49),x=(10(6-sqrt(379)))/(49)
Find the zeros of 4.9x^2-12x-70=0
The zeros of 4.9x^2-12x-70=0 are x=(10(6+sqrt(379)))/(49),x=(10(6-sqrt(379)))/(49)