What is factor 1/9 k^2-64 ?

The solution to factor 1/9 k^2-64 is (1/3 k+8)(1/3 k-8)

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factor 1/9 k^2-64

factor

\frac{1}{9} k^{2} - 64

(\frac{1}{3} k + 8) (\frac{1}{3} k - 8)

Solution steps

\frac{1}{9} k^{2} - 64

\frac{1}{9} k^{2} = (\frac{1}{3} k)^{2}

64 = 8^{2}

= (\frac{1}{3} k)^{2} - 8^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(\frac{1}{3} k)^{2} - 8^{2} = (\frac{1}{3} k + 8) (\frac{1}{3} k - 8)

= (\frac{1}{3} k + 8) (\frac{1}{3} k - 8)

\frac{7}{6} + \frac{3}{4}

\frac{r ^{4}}{r ^{6}}

\frac{- 16}{2}

a^{5} - 30 a^{3} - 25 a^{2} - 36 a - 180

2 y \cdot 3 x^{- 1} y^{4}

What is factor 1/9 k^2-64 ?
The solution to factor 1/9 k^2-64 is (1/3 k+8)(1/3 k-8)