What is the answer to |a-1|+4|a-3|=2|a+2| ?

The answer to |a-1|+4|a-3|=2|a+2| is a= 7/5 \lor a= 17/3

Solve for a: |a-1|+4|a-3|=2|a+2|

The solution is a= 7/5 \lor a= 17/3

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∣ a - 1 ∣ + 4 ∣ a - 3 ∣ = 2 ∣ a + 2 ∣

a = \frac{7}{5} or a = \frac{17}{3}

Solution steps

∣ a - 1 ∣ + 4 ∣ a - 3 ∣ = 2 ∣ a + 2 ∣

Find positive and negative intervals

a < - 2, - 2 \leq a < 1, 1 \leq a < 3, a \geq 3

Solve the inequality for each interval

No Solution or a = \frac{7}{5} or a = \frac{17}{3}

a = \frac{7}{5} or a = \frac{17}{3}

a x + b x + a y + b y

6 y^{2} - 5 y - 6 = 0

y^{3} - 8 z^{3}

8 - \frac{16}{3}

\frac{1}{6} \cdot 3

What is the answer to |a-1|+4|a-3|=2|a+2| ?
The answer to |a-1|+4|a-3|=2|a+2| is a= 7/5 \lor a= 17/3
Solve for a: |a-1|+4|a-3|=2|a+2|
The solution is a= 7/5 \lor a= 17/3