What are the solutions to the equation (5x-7)^2=12 ?

The solutions to the equation (5x-7)^2=12 are x=(2sqrt(3)+7)/5 ,x=(-2sqrt(3)+7)/5

Find the zeros of (5x-7)^2=12

The zeros of (5x-7)^2=12 are x=(2sqrt(3)+7)/5 ,x=(-2sqrt(3)+7)/5

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(5 x - 7)^{2} = 12

x = \frac{2 3 + 7}{5}, x = \frac{- 2 3 + 7}{5}

Solution steps

(5 x - 7)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 7 = 12 : x = \frac{2 3 + 7}{5}

Solve

5 x - 7 = - 12 : x = \frac{- 2 3 + 7}{5}

The solutions to the quadratic equation are:

x = \frac{2 3 + 7}{5}, x = \frac{- 2 3 + 7}{5}

- 8 q - 1 + 9 q = 9 + 4 q - 6

x^{2} - 4 x + 5 = 0

(\frac{( π + i )}{( π - i )})^{100}

(4 x + 1)^{2} = 6

(\frac{1}{2})^{2} + (\frac{1}{3})^{2}

What are the solutions to the equation (5x-7)^2=12 ?
The solutions to the equation (5x-7)^2=12 are x=(2sqrt(3)+7)/5 ,x=(-2sqrt(3)+7)/5
Find the zeros of (5x-7)^2=12
The zeros of (5x-7)^2=12 are x=(2sqrt(3)+7)/5 ,x=(-2sqrt(3)+7)/5