What are the solutions to the equation (4x+1)^2=6 ?

The solutions to the equation (4x+1)^2=6 are x=(sqrt(6)-1)/4 ,x=(-sqrt(6)-1)/4

Find the zeros of (4x+1)^2=6

The zeros of (4x+1)^2=6 are x=(sqrt(6)-1)/4 ,x=(-sqrt(6)-1)/4

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(4 x + 1)^{2} = 6

x = \frac{6 - 1}{4}, x = \frac{- 6 - 1}{4}

Decimal Notation

x = 0.36237 \dots, x = - 0.86237 \dots

Solution steps

(4 x + 1)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 1 = 6 : x = \frac{6 - 1}{4}

Solve

4 x + 1 = - 6 : x = \frac{- 6 - 1}{4}

The solutions to the quadratic equation are:

x = \frac{6 - 1}{4}, x = \frac{- 6 - 1}{4}

(\frac{1}{2})^{2} + (\frac{1}{3})^{2}

27 s + 9 t - 3

3 x^{2} - 41 x = - 110

- 3 x = - 12

- \frac{8}{7} = - \frac{5}{2} v - \frac{7}{3}

What are the solutions to the equation (4x+1)^2=6 ?
The solutions to the equation (4x+1)^2=6 are x=(sqrt(6)-1)/4 ,x=(-sqrt(6)-1)/4
Find the zeros of (4x+1)^2=6
The zeros of (4x+1)^2=6 are x=(sqrt(6)-1)/4 ,x=(-sqrt(6)-1)/4