What are the solutions to the equation x^2+6x-7=0 ?

The solutions to the equation x^2+6x-7=0 are x=1,x=-7

Find the zeros of x^2+6x-7=0

The zeros of x^2+6x-7=0 are x=1,x=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 6 x - 7 = 0

x = 1, x = - 7

Solution steps

x^{2} + 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 7) = 8

x_{1, 2} = \frac{- 6 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 8}{2 \cdot 1}, x_{2} = \frac{- 6 - 8}{2 \cdot 1}

x = \frac{- 6 + 8}{2 \cdot 1} : 1

x = \frac{- 6 - 8}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 1, x = - 7

x^{5} + 32

3 x^{3} + 2 x^{2} - 19 x + 6

x^{2} + 6 x + 9 = 0

3 (\frac{5}{6})^{2} - 5 (\frac{5}{6}) + 6

5 x^{2} - 40 x + 75

What are the solutions to the equation x^2+6x-7=0 ?
The solutions to the equation x^2+6x-7=0 are x=1,x=-7
Find the zeros of x^2+6x-7=0
The zeros of x^2+6x-7=0 are x=1,x=-7