What is 4(x^0)(y^{-2}) ?

The solution to 4(x^0)(y^{-2}) is 4/(y^2)

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simplify 4(x^0)(y^{-2})

simplify

4 (x^{0}) (y^{- 2})

\frac{4}{y ^{2}}

Solution steps

4 (x^{0}) (y^{- 2})

Simplify

4 (x^{0}) (y^{- 2}) : 4 x^{0} y^{- 2}

= 4 x^{0} y^{- 2}

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

x^{0} = 1

= 4 \cdot 1 \cdot y^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

y^{- 2} = \frac{1}{y ^{2}}

= 4 \cdot 1 \cdot \frac{1}{y ^{2}}

Multiply the numbers:

4 \cdot 1 = 4

= 4 \cdot \frac{1}{y ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{4 \cdot 1}{y ^{2}}

Multiply the numbers:

4 \cdot 1 = 4

= \frac{4}{y ^{2}}

(2 - b)^{3}

16 (a - 2) + 3 (10 - a)

2 (4 x + 2)

\frac{a ^{2} + 2 ab + b ^{2}}{3 a + 3 b}

- (2 x - 4.8 y) + 2.4