What are the solutions to the equation -x^2-3x+5=0 ?

The solutions to the equation -x^2-3x+5=0 are x=-(3+sqrt(29))/2 ,x=(sqrt(29)-3)/2

Find the zeros of -x^2-3x+5=0

The zeros of -x^2-3x+5=0 are x=-(3+sqrt(29))/2 ,x=(sqrt(29)-3)/2

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- x^{2} - 3 x + 5 = 0

x = - \frac{3 + 29}{2}, x = \frac{29 - 3}{2}

Decimal Notation

x = - 4.19258 \dots, x = 1.19258 \dots

Solution steps

- x^{2} - 3 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 5}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 5 = 29

x_{1, 2} = \frac{- ( - 3 ) \pm 29}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 29}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 29}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 29}{2 ( - 1 )} : - \frac{3 + 29}{2}

x = \frac{- ( - 3 ) - 29}{2 ( - 1 )} : \frac{29 - 3}{2}

The solutions to the quadratic equation are:

x = - \frac{3 + 29}{2}, x = \frac{29 - 3}{2}

\frac{4}{5} (x - 2) \leq \frac{1}{3} (x - 6)

- 3 t = 18

x^{2} + 18 x + 77 = 0

∣ 2 x - 3 ∣ < 4 - 2 x

5 x - 10 > - 26

What are the solutions to the equation -x^2-3x+5=0 ?
The solutions to the equation -x^2-3x+5=0 are x=-(3+sqrt(29))/2 ,x=(sqrt(29)-3)/2
Find the zeros of -x^2-3x+5=0
The zeros of -x^2-3x+5=0 are x=-(3+sqrt(29))/2 ,x=(sqrt(29)-3)/2