What are the solutions to the equation x^2+18x+77=0 ?

The solutions to the equation x^2+18x+77=0 are x=-7,x=-11

Find the zeros of x^2+18x+77=0

The zeros of x^2+18x+77=0 are x=-7,x=-11

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x^{2} + 18 x + 77 = 0

x = - 7, x = - 11

Solution steps

x^{2} + 18 x + 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 77}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 77 = 4

x_{1, 2} = \frac{- 18 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 4}{2 \cdot 1}, x_{2} = \frac{- 18 - 4}{2 \cdot 1}

x = \frac{- 18 + 4}{2 \cdot 1} : - 7

x = \frac{- 18 - 4}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = - 7, x = - 11

∣ 2 x - 3 ∣ < 4 - 2 x

5 x - 10 > - 26

4 v^{2} - 20 v = 0

\frac{- 8 - 7}{2 - ( - 4 )}

x^{2} - 9 > 0

What are the solutions to the equation x^2+18x+77=0 ?
The solutions to the equation x^2+18x+77=0 are x=-7,x=-11
Find the zeros of x^2+18x+77=0
The zeros of x^2+18x+77=0 are x=-7,x=-11