What are the solutions to the equation 9x^2+1=0 ?

The solutions to the equation 9x^2+1=0 are x= 1/3 i,x=-1/3 i

Find the zeros of 9x^2+1=0

The zeros of 9x^2+1=0 are x= 1/3 i,x=-1/3 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} + 1 = 0

x = \frac{1}{3} i, x = - \frac{1}{3} i

Solution steps

9 x^{2} + 1 = 0

Move

1

to the right side

9 x^{2} = - 1

Divide both sides by

9

x^{2} = - \frac{1}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{9}, x = - - \frac{1}{9}

- \frac{1}{9} = \frac{1}{3} i

- - \frac{1}{9} = - \frac{1}{3} i

x = \frac{1}{3} i, x = - \frac{1}{3} i

23 - x = 13

3 x^{2} + 6 x = 2

\frac{3 !}{2 ! ( 3 - 2 ) !}

y - 4 = - 2 (- 3 + 3)

4 x^{3} - 6 x^{2 - 28 x}

What are the solutions to the equation 9x^2+1=0 ?
The solutions to the equation 9x^2+1=0 are x= 1/3 i,x=-1/3 i
Find the zeros of 9x^2+1=0
The zeros of 9x^2+1=0 are x= 1/3 i,x=-1/3 i