What are the solutions to the equation r^2+3r=0 ?

The solutions to the equation r^2+3r=0 are r=0,r=-3

Find the zeros of r^2+3r=0

The zeros of r^2+3r=0 are r=0,r=-3

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r^{2} + 3 r = 0

r = 0, r = - 3

Solution steps

r^{2} + 3 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 0 = 3

r_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 3 + 3}{2 \cdot 1}, r_{2} = \frac{- 3 - 3}{2 \cdot 1}

r = \frac{- 3 + 3}{2 \cdot 1} : 0

r = \frac{- 3 - 3}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

r = 0, r = - 3

(0.05)^{2}

13 + k = 25

9 x^{2} - 2 x = 1

\frac{2}{2} - 1

lo g_{3} (x - 12) \leq 2

What are the solutions to the equation r^2+3r=0 ?
The solutions to the equation r^2+3r=0 are r=0,r=-3
Find the zeros of r^2+3r=0
The zeros of r^2+3r=0 are r=0,r=-3