What is (5-2i)-2(3+i) ?

The solution to (5-2i)-2(3+i) is -1-4i

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simplify (5-2i)-2(3+i)

simplify

(5 - 2 i) - 2 (3 + i)

- 1 - 4 i

Solution steps

(5 - 2 i) - 2 (3 + i)

Apply rule:

(a) = a

(5 - 2 i) = 5 - 2 i

= 5 - 2 i - 2 (3 + i)

Expand

- 2 (3 + i) : - 6 - 2 i

= 5 - 2 i - 6 - 2 i

Group like terms

= - 2 i - 2 i + 5 - 6

Add similar elements:

- 2 i - 2 i = - 4 i

= - 4 i + 5 - 6

Subtract the numbers:

5 - 6 = - 1

= - 4 i - 1

Rewrite in standard complex form:

- 1 - 4 i

= - 1 - 4 i

\frac{1}{3} 2

m^{4} n^{4} + m^{2} n^{2} - 132

(- 3 x^{2} - 3 x - 7) - (x^{2} + 8 x)

e^{\frac{1}{2} l n (1 - x^{2})}

\frac{7}{4} + \frac{8}{3}