What are the solutions to the equation 9x^2-2x=1 ?

The solutions to the equation 9x^2-2x=1 are x=(1+sqrt(10))/9 ,x=(1-sqrt(10))/9

Find the zeros of 9x^2-2x=1

The zeros of 9x^2-2x=1 are x=(1+sqrt(10))/9 ,x=(1-sqrt(10))/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} - 2 x = 1

x = \frac{1 + 10}{9}, x = \frac{1 - 10}{9}

Decimal Notation

x = 0.46247 \dots, x = - 0.24025 \dots

Solution steps

9 x^{2} - 2 x = 1

Move

1

to the left side

9 x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 9 ( - 1 )}{2 \cdot 9}

(- 2)^{2} - 4 \cdot 9 (- 1) = 210

x_{1, 2} = \frac{- ( - 2 ) \pm 2 10}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 10}{2 \cdot 9}, x_{2} = \frac{- ( - 2 ) - 2 10}{2 \cdot 9}

x = \frac{- ( - 2 ) + 2 10}{2 \cdot 9} : \frac{1 + 10}{9}

x = \frac{- ( - 2 ) - 2 10}{2 \cdot 9} : \frac{1 - 10}{9}

The solutions to the quadratic equation are:

x = \frac{1 + 10}{9}, x = \frac{1 - 10}{9}

\frac{2}{2} - 1

lo g_{3} (x - 12) \leq 2

5 x^{2} - 1 = 0

(6 (x + 1)^{5}) (x - 5)^{2} + (x + 1)^{6} \cdot 2 (x - 5)

\frac{3 x ^{7} y}{27 x ^{7} y ^{7}}

What are the solutions to the equation 9x^2-2x=1 ?
The solutions to the equation 9x^2-2x=1 are x=(1+sqrt(10))/9 ,x=(1-sqrt(10))/9
Find the zeros of 9x^2-2x=1
The zeros of 9x^2-2x=1 are x=(1+sqrt(10))/9 ,x=(1-sqrt(10))/9