What is (4(z)^2)/(-20z^{-6)} ?

The solution to (4(z)^2)/(-20z^{-6)} is -(z^8)/5

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simplify (4(z)^2)/(-20z^{-6)}

simplify

\frac{4 ( z ) ^{2}}{- 20 z ^{- 6}}

- \frac{z ^{8}}{5}

Solution steps

\frac{4 z ^{2}}{- 20 z ^{- 6}}

Factor the number:

20 = 4 \cdot 5

= \frac{4 z ^{2}}{- 4 \cdot 5 z ^{- 6}}

Cancel the common factor:

4

= \frac{z ^{2}}{- 5 z ^{- 6}}

Simplify

\frac{z ^{2}}{z ^{- 6}} : z^{8}

= \frac{z ^{8}}{- 5}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{z ^{8}}{5}

(x - 12) (x - 3)

(5 v)^{3}

\frac{( 3 + 4 i ) ( 1 - 2 i )}{1 + i}

(2 a + 1)^{3} - 2 (2 a + 1)^{2} + 20