What are the solutions to the equation 3x^2-10x-7=0 ?

The solutions to the equation 3x^2-10x-7=0 are x=(5+sqrt(46))/3 ,x=(5-sqrt(46))/3

Find the zeros of 3x^2-10x-7=0

The zeros of 3x^2-10x-7=0 are x=(5+sqrt(46))/3 ,x=(5-sqrt(46))/3

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3 x^{2} - 10 x - 7 = 0

x = \frac{5 + 46}{3}, x = \frac{5 - 46}{3}

Decimal Notation

x = 3.92744 \dots, x = - 0.59410 \dots

Solution steps

3 x^{2} - 10 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 10)^{2} - 4 \cdot 3 (- 7) = 246

x_{1, 2} = \frac{- ( - 10 ) \pm 2 46}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 46}{2 \cdot 3}, x_{2} = \frac{- ( - 10 ) - 2 46}{2 \cdot 3}

x = \frac{- ( - 10 ) + 2 46}{2 \cdot 3} : \frac{5 + 46}{3}

x = \frac{- ( - 10 ) - 2 46}{2 \cdot 3} : \frac{5 - 46}{3}

The solutions to the quadratic equation are:

x = \frac{5 + 46}{3}, x = \frac{5 - 46}{3}

\frac{( \frac{1}{4} )}{2}

∣ 4 x - 5 ∣ \leq 12

\frac{1}{2} x = 32

(1.6 \cdot 1 0^{- 19}) (375) (3.2 \frac{1}{100})

9 x^{2} \leq 24 x - 16

What are the solutions to the equation 3x^2-10x-7=0 ?
The solutions to the equation 3x^2-10x-7=0 are x=(5+sqrt(46))/3 ,x=(5-sqrt(46))/3
Find the zeros of 3x^2-10x-7=0
The zeros of 3x^2-10x-7=0 are x=(5+sqrt(46))/3 ,x=(5-sqrt(46))/3