What are the solutions to the equation -3=x^2+4x ?

The solutions to the equation -3=x^2+4x are x=-1,x=-3

Find the zeros of -3=x^2+4x

The zeros of -3=x^2+4x are x=-1,x=-3

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- 3 = x^{2} + 4 x

x = - 1, x = - 3

Solution steps

- 3 = x^{2} + 4 x

Switch sides

x^{2} + 4 x = - 3

Move

3

to the left side

x^{2} + 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 2}{2 \cdot 1}

x = \frac{- 4 + 2}{2 \cdot 1} : - 1

x = \frac{- 4 - 2}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

125 x^{9} - 27 y^{6}

- 40 (\frac{2 ( 10 b + 23 )}{25}) + 48 b = 17.2

- 5 < \frac{z}{- 1} - 8

2 - (- \frac{3}{4})^{2}

9 r^{3} s^{2} - 30 r s^{3}

What are the solutions to the equation -3=x^2+4x ?
The solutions to the equation -3=x^2+4x are x=-1,x=-3
Find the zeros of -3=x^2+4x
The zeros of -3=x^2+4x are x=-1,x=-3