What are the solutions to the equation 30-2x-(x^2)/9 =0 ?

The solutions to the equation 30-2x-(x^2)/9 =0 are x=-3(3+sqrt(39)),x=3(sqrt(39)-3)

Find the zeros of 30-2x-(x^2)/9 =0

The zeros of 30-2x-(x^2)/9 =0 are x=-3(3+sqrt(39)),x=3(sqrt(39)-3)

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30 - 2 x - \frac{x ^{2}}{9} = 0

x = - 3 (3 + 39), x = 3 (39 - 3)

Solution steps

30 - 2 x - \frac{x ^{2}}{9} = 0

Multiply both sides by

9

- x^{2} - 18 x + 270 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 ( - 1 ) \cdot 270}{2 ( - 1 )}

(- 18)^{2} - 4 (- 1) \cdot 270 = 639

x_{1, 2} = \frac{- ( - 18 ) \pm 6 39}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 39}{2 ( - 1 )}, x_{2} = \frac{- ( - 18 ) - 6 39}{2 ( - 1 )}

x = \frac{- ( - 18 ) + 6 39}{2 ( - 1 )} : - 3 (3 + 39)

x = \frac{- ( - 18 ) - 6 39}{2 ( - 1 )} : 3 (39 - 3)

The solutions to the quadratic equation are:

x = - 3 (3 + 39), x = 3 (39 - 3)

a^{20} - a^{10} + a^{5}

9 x^{2} - 12 x + 148 = 0

\frac{4}{3}

m^{2} = 16

\frac{x}{x - 1} > 0

What are the solutions to the equation 30-2x-(x^2)/9 =0 ?
The solutions to the equation 30-2x-(x^2)/9 =0 are x=-3(3+sqrt(39)),x=3(sqrt(39)-3)
Find the zeros of 30-2x-(x^2)/9 =0
The zeros of 30-2x-(x^2)/9 =0 are x=-3(3+sqrt(39)),x=3(sqrt(39)-3)