What are the solutions to the equation 2s^2+8s+8=0 ?

The solutions to the equation 2s^2+8s+8=0 are s=-2

Find the zeros of 2s^2+8s+8=0

The zeros of 2s^2+8s+8=0 are s=-2

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2 s^{2} + 8 s + 8 = 0

s = - 2

Solution steps

2 s^{2} + 8 s + 8 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 8 = 0

s_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 2}

s = \frac{- 8}{2 \cdot 2}

\frac{- 8}{2 \cdot 2} = - 2

s = - 2

The solution to the quadratic equation is:

s = - 2

5 - 3 z + 3 (3 - 5 z) = 12

\frac{k ^{2} - k - 2}{k ^{2} - 4 k - 5}

(x - 4) (x - 5) = 0

\frac{x + 1}{2 - x} \leq \frac{x}{x + 3}

\frac{x - 2}{2 x - 1} < 3

What are the solutions to the equation 2s^2+8s+8=0 ?
The solutions to the equation 2s^2+8s+8=0 are s=-2
Find the zeros of 2s^2+8s+8=0
The zeros of 2s^2+8s+8=0 are s=-2