What are the solutions to the equation (x-4)(x-5)=0 ?

The solutions to the equation (x-4)(x-5)=0 are x=4,x=5

Find the zeros of (x-4)(x-5)=0

The zeros of (x-4)(x-5)=0 are x=4,x=5

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(x - 4) (x - 5) = 0

x = 4, x = 5

Solution steps

(x - 4) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x - 5 = 0

Solve

x - 4 = 0 : x = 4

Solve

x - 5 = 0 : x = 5

The solutions to the quadratic equation are:

x = 4, x = 5

\frac{x + 1}{2 - x} \leq \frac{x}{x + 3}

\frac{x - 2}{2 x - 1} < 3

10 x^{2} - 2 x = 0

x^{4} y^{4} - 2 x^{2} y^{2} - 99

2 (2 x - 3) > - 8 x + 12

What are the solutions to the equation (x-4)(x-5)=0 ?
The solutions to the equation (x-4)(x-5)=0 are x=4,x=5
Find the zeros of (x-4)(x-5)=0
The zeros of (x-4)(x-5)=0 are x=4,x=5