What is (2x+1)(2x-1)-(x+4)^2 ?

The solution to (2x+1)(2x-1)-(x+4)^2 is 3x^2-8x-17

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simplify (2x+1)(2x-1)-(x+4)^2

simplify

(2 x + 1) (2 x - 1) - (x + 4)^{2}

3 x^{2} - 8 x - 17

Solution steps

(2 x + 1) (2 x - 1) - (x + 4)^{2}

Expand

(2 x + 1) (2 x - 1) : 4 x^{2} - 1

= 4 x^{2} - 1 - (x + 4)^{2}

Expand

- (x + 4)^{2} : - x^{2} - 8 x - 16

= 4 x^{2} - 1 - x^{2} - 8 x - 16

Group like terms

= 4 x^{2} - x^{2} - 8 x - 1 - 16

Add similar elements:

4 x^{2} - x^{2} = 3 x^{2}

= 3 x^{2} - 8 x - 1 - 16

Subtract the numbers:

- 1 - 16 = - 17

= 3 x^{2} - 8 x - 17

(7 p + 4 p^{3} - 8) - (- 3 p^{2} + 2 - 9 p)

(- 3 + 2 i) - (4 - 4 i)

2 \div \frac{4}{3}

i^{2666}

\frac{1}{\frac{1}{a}}

What is (2x+1)(2x-1)-(x+4)^2 ?
The solution to (2x+1)(2x-1)-(x+4)^2 is 3x^2-8x-17