What is factor 49x^2-28xy+4y^2 ?

The solution to factor 49x^2-28xy+4y^2 is (7x-2y)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 49x^2-28xy+4y^2

factor

49 x^{2} - 28 x y + 4 y^{2}

(7 x - 2 y)^{2}

Solution steps

49 x^{2} - 28 x y + 4 y^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

49 x^{2} = (7 x)^{2}

4 y^{2} = (2 y)^{2}

- 28 x y = - 2 \cdot 7 x \cdot 2 y

= (7 x)^{2} - 2 \cdot 7 x \cdot 2 y + (2 y)^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(7 x)^{2} - 2 \cdot 7 x \cdot 2 y + (2 y)^{2} = (7 x - 2 y)^{2}

= (7 x - 2 y)^{2}

\frac{400}{50}

(4 + 3 i) (4 + 2 i) - (2 + i) (3 - 4 i)

- 0.8 (- a - 1) + 0.3 a

- 2 x^{2} - 5

x^{3} + 6 x^{2} - 15 x - 90

What is factor 49x^2-28xy+4y^2 ?
The solution to factor 49x^2-28xy+4y^2 is (7x-2y)^2