What are the solutions to the equation x^2-6x+6=-2 ?

The solutions to the equation x^2-6x+6=-2 are x=4,x=2

Find the zeros of x^2-6x+6=-2

The zeros of x^2-6x+6=-2 are x=4,x=2

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x^{2} - 6 x + 6 = - 2

x = 4, x = 2

Solution steps

x^{2} - 6 x + 6 = - 2

Move

2

to the left side

x^{2} - 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2}{2 \cdot 1} : 4

x = \frac{- ( - 6 ) - 2}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 4, x = 2

4 \cdot 18

4 x^{2} - 48 = 0

(64 x^{- 12} y^{- 6})^{- \frac{1}{2}}

c^{2} - 9 c d + 18 d^{2}

32 \cdot 2

What are the solutions to the equation x^2-6x+6=-2 ?
The solutions to the equation x^2-6x+6=-2 are x=4,x=2
Find the zeros of x^2-6x+6=-2
The zeros of x^2-6x+6=-2 are x=4,x=2