What are the solutions to the equation -2(x+4)^2=8 ?

The solutions to the equation -2(x+4)^2=8 are x=2i-4,x=-2i-4

Find the zeros of -2(x+4)^2=8

The zeros of -2(x+4)^2=8 are x=2i-4,x=-2i-4

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- 2 (x + 4)^{2} = 8

x = 2 i - 4, x = - 2 i - 4

Solution steps

- 2 (x + 4)^{2} = 8

Divide both sides by

- 2

(x + 4)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = - 4 : x = 2 i - 4

Solve

x + 4 = - - 4 : x = - 2 i - 4

The solutions to the quadratic equation are:

x = 2 i - 4, x = - 2 i - 4

3 + 3

\frac{( \frac{3}{2} )}{3}

\frac{1}{4} \cdot \frac{1}{8}

7 x^{2} - 3 x = 4

4 3^{2}

What are the solutions to the equation -2(x+4)^2=8 ?
The solutions to the equation -2(x+4)^2=8 are x=2i-4,x=-2i-4
Find the zeros of -2(x+4)^2=8
The zeros of -2(x+4)^2=8 are x=2i-4,x=-2i-4