What are the solutions to the equation 50x^2-75x-17=0 ?

The solutions to the equation 50x^2-75x-17=0 are x= 17/10 ,x=-1/5

Find the zeros of 50x^2-75x-17=0

The zeros of 50x^2-75x-17=0 are x= 17/10 ,x=-1/5

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50 x^{2} - 75 x - 17 = 0

x = \frac{17}{10}, x = - \frac{1}{5}

Decimal Notation

x = 1.7, x = - 0.2

Solution steps

50 x^{2} - 75 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 75 ) \pm ( - 75 ) ^{2} - 4 \cdot 50 ( - 17 )}{2 \cdot 50}

(- 75)^{2} - 4 \cdot 50 (- 17) = 95

x_{1, 2} = \frac{- ( - 75 ) \pm 95}{2 \cdot 50}

Separate the solutions

x_{1} = \frac{- ( - 75 ) + 95}{2 \cdot 50}, x_{2} = \frac{- ( - 75 ) - 95}{2 \cdot 50}

x = \frac{- ( - 75 ) + 95}{2 \cdot 50} : \frac{17}{10}

x = \frac{- ( - 75 ) - 95}{2 \cdot 50} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{17}{10}, x = - \frac{1}{5}

2 x = x

4 (x + 6) = 32

2 [7 - 5 (1 - n)] + 8 n = - 16 + 3 [6 (n + 1) - 3 n]

x^{4} \leq x^{2}

2 (4 x + 3) = 10 x - 2

What are the solutions to the equation 50x^2-75x-17=0 ?
The solutions to the equation 50x^2-75x-17=0 are x= 17/10 ,x=-1/5
Find the zeros of 50x^2-75x-17=0
The zeros of 50x^2-75x-17=0 are x= 17/10 ,x=-1/5