What are the solutions to the equation 5x^2+7x-1=0 ?

The solutions to the equation 5x^2+7x-1=0 are x=(-7+sqrt(69))/(10),x=(-7-sqrt(69))/(10)

Find the zeros of 5x^2+7x-1=0

The zeros of 5x^2+7x-1=0 are x=(-7+sqrt(69))/(10),x=(-7-sqrt(69))/(10)

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5 x^{2} + 7 x - 1 = 0

x = \frac{- 7 + 69}{10}, x = \frac{- 7 - 69}{10}

Decimal Notation

x = 0.13066 \dots, x = - 1.53066 \dots

Solution steps

5 x^{2} + 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

7^{2} - 4 \cdot 5 (- 1) = 69

x_{1, 2} = \frac{- 7 \pm 69}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 7 + 69}{2 \cdot 5}, x_{2} = \frac{- 7 - 69}{2 \cdot 5}

x = \frac{- 7 + 69}{2 \cdot 5} : \frac{- 7 + 69}{10}

x = \frac{- 7 - 69}{2 \cdot 5} : \frac{- 7 - 69}{10}

The solutions to the quadratic equation are:

x = \frac{- 7 + 69}{10}, x = \frac{- 7 - 69}{10}

x^{2} - 8 x + 10 = 0

7 x^{2} + 6 = 0

5 x + 7 = 12

∣ 2 x - 5 ∣ \leq 9

(x^{2} - y^{2}) - ((x + y) (x - y)) + 3 x^{2}

What are the solutions to the equation 5x^2+7x-1=0 ?
The solutions to the equation 5x^2+7x-1=0 are x=(-7+sqrt(69))/(10),x=(-7-sqrt(69))/(10)
Find the zeros of 5x^2+7x-1=0
The zeros of 5x^2+7x-1=0 are x=(-7+sqrt(69))/(10),x=(-7-sqrt(69))/(10)