What is (15x^4y^2z)/(-3xy^6z^3) ?

The solution to (15x^4y^2z)/(-3xy^6z^3) is -(5x^3)/(y^4z^2)

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simplify (15x^4y^2z)/(-3xy^6z^3)

simplify

\frac{15 x ^{4} y ^{2} z}{- 3 x y ^{6} z ^{3}}

- \frac{5 x ^{3}}{y ^{4} z ^{2}}

Solution steps

\frac{15 x ^{4} y ^{2} z}{- 3 x y ^{6} z ^{3}}

Factor the number:

15 = 3 \cdot 5

= \frac{3 \cdot 5 x ^{4} y ^{2} z}{- 3 x y ^{6} z ^{3}}

Cancel the common factor:

3

= \frac{5 x ^{4} y ^{2} z}{- x y ^{6} z ^{3}}

Simplify

\frac{x ^{4}}{x} : x^{3}

= \frac{5 x ^{3} y ^{2} z}{- y ^{6} z ^{3}}

Simplify

\frac{y ^{2}}{y ^{6}} : \frac{1}{y ^{4}}

= \frac{5 x ^{3} z}{- y ^{4} z ^{3}}

Simplify

\frac{z}{z ^{3}} : \frac{1}{z ^{2}}

= \frac{5 x ^{3}}{- y ^{4} z ^{2}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{5 x ^{3}}{y ^{4} z ^{2}}

14 x^{2} + 7 x - 21

- 3 x^{2} + 8 x - 1 = 0

\frac{8}{3 - x} \leq 2

lo g_{7}^{2} (\frac{1}{49})

- 2 (x - 3)^{2} > 0

What is (15x^4y^2z)/(-3xy^6z^3) ?
The solution to (15x^4y^2z)/(-3xy^6z^3) is -(5x^3)/(y^4z^2)