What are the solutions to the equation -3x^2+8x-1=0 ?

The solutions to the equation -3x^2+8x-1=0 are x=(4-sqrt(13))/3 ,x=(4+sqrt(13))/3

Find the zeros of -3x^2+8x-1=0

The zeros of -3x^2+8x-1=0 are x=(4-sqrt(13))/3 ,x=(4+sqrt(13))/3

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- 3 x^{2} + 8 x - 1 = 0

x = \frac{4 - 13}{3}, x = \frac{4 + 13}{3}

Decimal Notation

x = 0.13148 \dots, x = 2.53518 \dots

Solution steps

- 3 x^{2} + 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 3 ) ( - 1 )}{2 ( - 3 )}

8^{2} - 4 (- 3) (- 1) = 213

x_{1, 2} = \frac{- 8 \pm 2 13}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 13}{2 ( - 3 )}, x_{2} = \frac{- 8 - 2 13}{2 ( - 3 )}

x = \frac{- 8 + 2 13}{2 ( - 3 )} : \frac{4 - 13}{3}

x = \frac{- 8 - 2 13}{2 ( - 3 )} : \frac{4 + 13}{3}

The solutions to the quadratic equation are:

x = \frac{4 - 13}{3}, x = \frac{4 + 13}{3}

\frac{8}{3 - x} \leq 2

lo g_{7}^{2} (\frac{1}{49})

- 2 (x - 3)^{2} > 0

3 b (9 b - 27) = 0

x^{2} + 28 x + 83 = 9 x - 7

What are the solutions to the equation -3x^2+8x-1=0 ?
The solutions to the equation -3x^2+8x-1=0 are x=(4-sqrt(13))/3 ,x=(4+sqrt(13))/3
Find the zeros of -3x^2+8x-1=0
The zeros of -3x^2+8x-1=0 are x=(4-sqrt(13))/3 ,x=(4+sqrt(13))/3