What are the solutions to the equation x^2+28x+83=9x-7 ?

The solutions to the equation x^2+28x+83=9x-7 are x=-9,x=-10

Find the zeros of x^2+28x+83=9x-7

The zeros of x^2+28x+83=9x-7 are x=-9,x=-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 28 x + 83 = 9 x - 7

x = - 9, x = - 10

Solution steps

x^{2} + 28 x + 83 = 9 x - 7

Move

7

to the left side

x^{2} + 28 x + 90 = 9 x

Move

9 x

to the left side

x^{2} + 19 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 1 \cdot 90}{2 \cdot 1}

1 9^{2} - 4 \cdot 1 \cdot 90 = 1

x_{1, 2} = \frac{- 19 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 19 + 1}{2 \cdot 1}, x_{2} = \frac{- 19 - 1}{2 \cdot 1}

x = \frac{- 19 + 1}{2 \cdot 1} : - 9

x = \frac{- 19 - 1}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 9, x = - 10

\frac{3 + i}{2 - i} + \frac{1}{1 + i}

7 x^{2} - 16 x = 8

x^{2} + 8 x + 12 = 0

6 x^{2} + x - 15

s^{3} + 6 s^{2} + 11 s + 6

What are the solutions to the equation x^2+28x+83=9x-7 ?
The solutions to the equation x^2+28x+83=9x-7 are x=-9,x=-10
Find the zeros of x^2+28x+83=9x-7
The zeros of x^2+28x+83=9x-7 are x=-9,x=-10