What is expand (2x^2-3)(2x^2+3) ?

The solution to expand (2x^2-3)(2x^2+3) is 4x^4-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x^2-3)(2x^2+3)

expand

(2 x^{2} - 3) (2 x^{2} + 3)

4 x^{4} - 9

Solution steps

(2 x^{2} - 3) (2 x^{2} + 3)

Apply Difference of Two Squares

(2 x^{2} - 3) (2 x^{2} + 3) : 4 x^{4} - 9

= 4 x^{4} - 9

x^{8} + 4 x^{6} - 4 x^{2} - 1

\frac{r ^{2}}{r ^{2}}

(5 - 3 i) + (- 2 + - 9)

- 2 \cdot (- 12)

2 \cdot \frac{1}{16}

What is expand (2x^2-3)(2x^2+3) ?
The solution to expand (2x^2-3)(2x^2+3) is 4x^4-9