What are the solutions to the equation 0=40-490t^2 ?

The solutions to the equation 0=40-490t^2 are t= 2/7 ,t=-2/7

Find the zeros of 0=40-490t^2

The zeros of 0=40-490t^2 are t= 2/7 ,t=-2/7

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0 = 40 - 490 t^{2}

t = \frac{2}{7}, t = - \frac{2}{7}

Decimal Notation

t = 0.28571 \dots, t = - 0.28571 \dots

Solution steps

0 = 40 - 490 t^{2}

Switch sides

40 - 490 t^{2} = 0

Move

40

to the right side

- 490 t^{2} = - 40

Divide both sides by

- 490

t^{2} = \frac{4}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{4}{49}, t = - \frac{4}{49}

\frac{4}{49} = \frac{2}{7}

- \frac{4}{49} = - \frac{2}{7}

t = \frac{2}{7}, t = - \frac{2}{7}

5 x^{2} - 17 x - 40 = 0

1 + \frac{2}{3}

3 x^{3} - x^{2} - 75 x + 25 < 0

x^{2} + 5 x + 4 < 0

5.1 (3 + 2.2 x) > - 14.25 - 6 (1.7 x + 4)

What are the solutions to the equation 0=40-490t^2 ?
The solutions to the equation 0=40-490t^2 are t= 2/7 ,t=-2/7
Find the zeros of 0=40-490t^2
The zeros of 0=40-490t^2 are t= 2/7 ,t=-2/7