What is factor 81x^{12}-1 ?

The solution to factor 81x^{12}-1 is (9x^6+1)(3x^3+1)(3x^3-1)

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factor 81x^{12}-1

factor

81 x^{12} - 1

(9 x^{6} + 1) (3 x^{3} + 1) (3 x^{3} - 1)

Solution steps

81 x^{12} - 1

Apply exponent rules

= (9 x^{6})^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(9 x^{6})^{2} - 1^{2} = (9 x^{6} + 1) (9 x^{6} - 1)

= (9 x^{6} + 1) (9 x^{6} - 1)

Factor

9 x^{6} - 1 : (3 x^{3} + 1) (3 x^{3} - 1)

= (9 x^{6} + 1) (3 x^{3} + 1) (3 x^{3} - 1)

(3 x + 1) (2 x - 4)

40 (2.1) - 16 (2.1)^{2}

\frac{3}{5} \div \frac{10}{3}

(4 r^{2})^{6}

a^{2} - 2 a + 5 a^{3} + 1 - 10 a

What is factor 81x^{12}-1 ?
The solution to factor 81x^{12}-1 is (9x^6+1)(3x^3+1)(3x^3-1)