What are the solutions to the equation x(x+4)=-13 ?

The solutions to the equation x(x+4)=-13 are x=-2+3i,x=-2-3i

Find the zeros of x(x+4)=-13

The zeros of x(x+4)=-13 are x=-2+3i,x=-2-3i

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x (x + 4) = - 13

x = - 2 + 3 i, x = - 2 - 3 i

Solution steps

x (x + 4) = - 13

Expand

x (x + 4) : x^{2} + 4 x

x^{2} + 4 x = - 13

Move

13

to the left side

x^{2} + 4 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 13 : 6 i

x_{1, 2} = \frac{- 4 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 6 i}{2 \cdot 1}

x = \frac{- 4 + 6 i}{2 \cdot 1} : - 2 + 3 i

x = \frac{- 4 - 6 i}{2 \cdot 1} : - 2 - 3 i

The solutions to the quadratic equation are:

x = - 2 + 3 i, x = - 2 - 3 i

5 x + 2 = 32

3 x^{3} - 2 x^{2} + 5 x + 2

x^{2} + 6 x - 1 > 6

125 - m^{3}

1 + a^{7}

What are the solutions to the equation x(x+4)=-13 ?
The solutions to the equation x(x+4)=-13 are x=-2+3i,x=-2-3i
Find the zeros of x(x+4)=-13
The zeros of x(x+4)=-13 are x=-2+3i,x=-2-3i