What are the solutions to the equation m^2-8m-16=-16 ?

The solutions to the equation m^2-8m-16=-16 are m=8,m=0

Find the zeros of m^2-8m-16=-16

The zeros of m^2-8m-16=-16 are m=8,m=0

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m^{2} - 8 m - 16 = - 16

m = 8, m = 0

Solution steps

m^{2} - 8 m - 16 = - 16

Move

16

to the left side

m^{2} - 8 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

m_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, m_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

m = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

m = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

m = 8, m = 0

4 + - 25

\frac{3 x - 2}{4} - \frac{2 x - 5}{3} = \frac{1 + x}{6}

3 (- 2 x + 1) - 2 (x + 13) = 7 x - 4 (1 - x)

- 7 < 3 x + 2 \leq 19

x^{2} - 10 = 62

What are the solutions to the equation m^2-8m-16=-16 ?
The solutions to the equation m^2-8m-16=-16 are m=8,m=0
Find the zeros of m^2-8m-16=-16
The zeros of m^2-8m-16=-16 are m=8,m=0