What are the solutions to the equation 36-25x+4x^2=0 ?

The solutions to the equation 36-25x+4x^2=0 are x=4,x= 9/4

Find the zeros of 36-25x+4x^2=0

The zeros of 36-25x+4x^2=0 are x=4,x= 9/4

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36 - 25 x + 4 x^{2} = 0

x = 4, x = \frac{9}{4}

Decimal Notation

x = 4, x = 2.25

Solution steps

36 - 25 x + 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 25 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 4 \cdot 36}{2 \cdot 4}

(- 25)^{2} - 4 \cdot 4 \cdot 36 = 7

x_{1, 2} = \frac{- ( - 25 ) \pm 7}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 7}{2 \cdot 4}, x_{2} = \frac{- ( - 25 ) - 7}{2 \cdot 4}

x = \frac{- ( - 25 ) + 7}{2 \cdot 4} : 4

x = \frac{- ( - 25 ) - 7}{2 \cdot 4} : \frac{9}{4}

The solutions to the quadratic equation are:

x = 4, x = \frac{9}{4}

(b + 12)^{2} = 81

28 > 4 n

5 x^{2} - 55 = 90

\frac{3 \cdot 180}{2}

\frac{x ^{15}}{x ^{10}}

What are the solutions to the equation 36-25x+4x^2=0 ?
The solutions to the equation 36-25x+4x^2=0 are x=4,x= 9/4
Find the zeros of 36-25x+4x^2=0
The zeros of 36-25x+4x^2=0 are x=4,x= 9/4